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-.4x^2+2.7x+8=0
We add all the numbers together, and all the variables
-0.4x^2+2.7x+8=0
a = -0.4; b = 2.7; c = +8;
Δ = b2-4ac
Δ = 2.72-4·(-0.4)·8
Δ = 20.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.7)-\sqrt{20.09}}{2*-0.4}=\frac{-2.7-\sqrt{20.09}}{-0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.7)+\sqrt{20.09}}{2*-0.4}=\frac{-2.7+\sqrt{20.09}}{-0.8} $
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